The See-Saw

 

  Mass   Volume   Number of Particles
mole Ar/ Mr Ξ 24 dm3 at r.t.p Ξ 6.0 X 1023

                                                                                     

            

Cations

                        
  Coloured     White     None  
                       
  NaOH (aq) NH3 (aq)     NaOH (aq) NH3(aq)     NaOH (aq) NH3(aq)  
Cu2+  I *S   Zn2+ S S   Ca2+ *I -  
Fe2+ I I   Al3+ S I   NH4+ - -  
Fe3+ I I   Pb2+ S I          

 

 

Anions

                       
  Coloured     White     None  
                       
  Reagent Pdt     Reagent Pdt     Reagent Pdt  
I- H+ / Pb(NO3)2 PbI2   Cl- H+ / AgNO3 AgCl   NO3-

Al/ NaOH

Heat

NH3  
        SO42-  H+ / Ba(NO3)2

 

BaSO4

 

  CO32-  H+  CO2  
                       
I   Pee on Ch  SO  

     Ag      Ba

with 

NO   CO 

 

NH3 CO

 

(A) Naming of ionic compounds [ 'Metal' + 'Non-metal' ]

Pre-requisites

A1) Write on top of the Roman numerals of the Periodic Table 1+ 2+ 3+ ..... as shown below.

  1+ 2+    3+ 4+/4- 3- 2- 1- 0  
  I II   III IV V VI VII 0  

 

A2) Highlight the elements as shown below. Call this 'a 7 and a dot'. These standalone elements will always be       

        written as X2. They are diatomic.

  I II   III IV V VI VII 0  
      H              
            N O F    
                Cl    
                Br    
                I    
                At    

 

A3) Memorise these commonly used polyatomic ions.   

 
   NH4+  NO3- OH-  HCO3- CO32- SO42-   SO32-   PO43-  
   ammonium   nitrate  hydroxide  hydrogencarbonate   carbonate   sulfate  sulfite   phosphate  

 

A4) For metal ions with Roman Numerals, they are either transition metals or Group IV metals, the charge of the

       metal ion follows the Roman Numerals assigned.  

(i)   iron (II) ...       means charge of iron is 2+.         It is written as Fe2+.

(ii)  iron (III) ...     means charge of iron is 3+.         It is written as Fe3+.

(iii) copper (I) ...    means charge of copper is 1+.    It is written as Cu+.

(iv) copper (II) ...  means charge of copper is 2+.    It is written as Cu2+.

(v)  lead (II) ....     means charge of lead is 2+.        It is written as  Pb2+.

(vi) lead (IV) ....     means charge of lead is 4+.        It is written as  Pb4+.

 

 


Q1 : Chemical formula of calcium chloride.
 

A1 : Step 1 : Now, look at the Periodic Table and refer to A1. Write down Ca2+ and Cl-.

        Step 2 : Cross 'number only NOT CHARGES' to bottom of the element. Hence, Ca is 1 and Cl is 2 like this. Ca1Cl2

        Step 3 : There is no need to put 1 for Ca as it is understood as '1' NOT '0'. Therefore, final answer : CaCl2

 

Q2 : Chemical formula of sodium chloride

A2 : Step 1 : Now, look at the Periodic Table and refer to A1. Write down Na+ and Cl-.

        Step 2 : If the numerically charges are the same (e.g 1+  1- or 2+  2- or 3+  3- , ignore crossing and simply write as, in   

                      this case, NaCl.)

 

Q3 : Chemical formula of calcium hydroxide

A3 : Step 1 : Now, look at the Periodic Table and refer to A1, write down Ca2+. Refer to A3, write down OH-.

        Step 2 : Cross 'number only NOT CHARGES' to bottom of the ions. Hence, Ca is 1 and OH is 2 like this Ca1OH2

         Step 3 : Since OH- is polyatomic ion, bracket (OH). Ignore '1' for Ca to get the final answer Ca(OH)2.

 

Q4 : Chemical formula of iron (III) sulfate

A4 : Step 1 : Refer to A4, write down Fe3+. Refer to A3, write down SO42-.

        Step 2 : Cross 'number only NOT CHARGES' to bottom of the ions. Hence, Fe is 2 and SO4 is 3 like this Fe2SO4 3

         Step 3 : Since SO42- is polyatomic ion, bracket (SO4) to get the final answer Fe2(SO4)3.

 


 

(B) Naming of covalent compounds  [ Non-metal + Non-metal ]

 Pre-requisites

B1) Memorise the prefixes of the following.

 
   1  2 3  4 5 6  7   8 9 10  
   mono-  di- or bi-  tri- tetra-  penta-   hexa-  hepta-  octa nona- deca-  

 

 

Q1 : Chemical formula of carbon dioxide.

A1 : Step 1 : Now, look at the Periodic Table and look for the symbol of carbon. Write down C.

        Step 2 : Oxide comes from the element oxygen. Now look for symbol oxygen. Write down O.

        Step 3 : Refer to B1. 'di' means 2. Therefore, final answer is CO2. Note : O comes first, then 2.

 

Q2 : Chemical formula of sulfur trioxide.

A2 : Step 1 : Now, look at the Periodic Table and look for the symbol of sulfur. Write down S.

        Step 2 : Oxide comes from the element oxygen. Now look for symbol oxygen. Write down O.

        Step 3 : Refer to B1. 'tri' means 3. Therefore, final answer is SO3Note : O comes first, then 3.

 

Q3 : Chemical formula of dinitrogen tetroxide.

A4 : Step 1 : Now, look at the Periodic Table and look for the symbol of nitrogen. Write down N.

        Step 2 : Oxide comes from the element oxygen. Now look for symbol oxygen. Write down O.

        Step 3 : Refer to B1. 'di' means 2 and 'tetra' means 4. Therefore, final answer is N2O4

        Note : N comes first, then 2. O comes first, then 4.

       

       Suppose you follow the writing of the chemical formula, the name should be sulfur oxide-tri or carbon oxide-di. As this naming

       sounds awkward, the naming convention follows that the prefix precedes the element.

 


 

(C) Naming of acids and bases

Pre-requisites

C1)  Mineral acids have a 'H' in front while inorganic bases have an 'O' or 'OH' behind.

C2)  Aqueous ammonia is the only base without 'O' or 'OH' behind in the chemical formula and it is written as       

        NH3 (aq).

        (Note : Ammonium hydroxide does not exist.)

C3)  Organic acids have a '-COOH' behind while organic bases have a '-NH2' behind.

C4)  Prefixes of organic compounds. 

 
No. of carbon atoms   1   2 3  4 5 6  7  8  
Prefix  meth-   eth-  prop-  but-  pent-   hex-  hept-   oct-  
Structural Prefix CH3 C2H5 C3H7 C4H9 C5H11 C6H13 C7H15 C8H17  

 

 

 

Q1 : Chemical formula of sulfuric acid

A1 : Step 1 : Refer to C1, write down H+. Refer to A3, write down SO42- as sulfuric comes from sulfate.

                     Note : All '-ric' comes from '-ate' & '-rous' comes from '-ite'.

        Step 2 : Cross 'number only NOT CHARGES' to bottom of the ions. Hence, H is 2 and SO4 is 1 like this H2SO4 1

         Step 3 : SO42- is polyatomic ion, bracket (SO4)1 but this is redundant as (SO4)1 is understood as SO4.

                      Final answer : H2SO4.

 

Q2 : Chemical formula of ethanoic acid

A2 : Step 1 : Refer to C3, write down COOH as it is an organic acid, -oic acid. Refer to C4, write CH3 NOT C2Has the     

                      C in COOH contributes to 1 carbon. Naming is based on the number of carbon atoms present in compound.

        Step 2 : Combine them and you get CH3COOH.

 

Q3: Chemical formula of iron (III) hydroxide

A4 : Step 1 : Refer to A4, write down Fe3+. Refer to A3, write down OH-.

        Step 2 : Cross 'number only NOT CHARGES' to bottom of the ions. Hence, Fe is 1 and OH is 3 like this FeOH 3

         Step 3 : Since OH- is polyatomic ion, bracket (OH) and ignore '1' to get the final answer Fe(OH)3.

 

Q4 : Chemical formula of methylamine

A4 : Step 1 : Refer to C3, write down NH2 as it is an organic base, -amine. Refer to C4, write CHas it is a methyl. 

        Step 2 : Combine them and you get CH3NH2.

 

General rule of the thumb : Non-metal + Non-metal --> Covalent


STEP 1

Identify the Group the non-metals belong to.

For example in H2O, O atom belongs to Group VI (2- hence 2 lines) while

                                   H atom is unplaced but has 1 lone electron (1- hence 1 line).

 

STEP 2

Identify the Period the non-metals belong to and overlap the outermost electron shells.

atom belongs to Period 2 hence draw 2 concentric circles while

H atom belongs to Period 1 hence draw 1 circle

(Ensure that the outermost circles overlap to house the shared electrons as shown below.)

Single bond = 1 pair of shared electrons.      'x•'  

Double bond = 2 pairs of shared electrons.   'x•x•'

Triple bond = 3 pairs of shared electrons.     'x•x•x•'

 

 

STEP 3

Fill in the Remaining Unbonded electrons for the elements and include the Legend.

In this case for O, 4 'x' electrons for outermost shell and 2 'x' electrons in the first shell.

Count the total number of outermost electrons of each atom. O atom is 8 while H atom is 2. 

The stable noble gas electronic configuration of the outermost electrons is either 8 or 2